# Greetings from The On-Line Encyclopedia of Integer Sequences! http://oeis.org/ Search: id:a116525 Showing 1-1 of 1 %I A116525 #44 Mar 06 2023 18:07:12 %S A116525 0,1,11,21,121,131,231,331,1331,1341,1441,1541,2541,2641,3641,4641, %T A116525 14641,14651,14751,14851,15851,15951,16951,17951,27951,28051,29051, %U A116525 30051,40051,41051,51051,61051,161051,161061,161161,161261,162261,162361,163361,164361 %N A116525 a(0)=1, a(1)=1, a(n) = 11*a(n/2) for even n, and a(n) = 10*a((n-1)/2) + a((n+1)/2) for odd n >= 3. %C A116525 From _Gary W. Adamson_, Aug 30 2016: (Start) %C A116525 Let M = %C A116525 1, 0, 0, 0, 0, ... %C A116525 11, 0, 0, 0, 0, ... %C A116525 10, 1, 0, 0, 0, ... %C A116525 0, 11, 0, 0, 0, ... %C A116525 0, 10, 1, 0, 0, ... %C A116525 0, 0, 11, 0, 0, ... %C A116525 0, 0, 10, 1, 0, ... %C A116525 ... %C A116525 Then lim_{k->infinity} M^k converges to a single nonzero column giving the sequence. %C A116525 The sequence divided by its aerated variant is (1, 11, 10, 0, 0, 0, ...). (End) %H A116525 Alois P. Heinz, Table of n, a(n) for n = 0..16383 (first 2501 terms from G. C. Greubel) %H A116525 H. Harborth, Number of Odd Binomial Coefficients, Proc. Amer. Math. Soc. 62, 19-22, 1977. %H A116525 Hsien-Kuei Hwang, Svante Janson, and Tsung-Hsi Tsai, Identities and periodic oscillations of divide-and-conquer recurrences splitting at half, arXiv:2210.10968 [cs.DS], 2022, pp. 27, 33. %H A116525 Eric Weisstein's World of Mathematics, Stolarsky-Harborth Constant %F A116525 Let r(x) = (1 + 11x + 10x^2). The sequence is r(x) * r(x^2) * r(x^4) * r(x^8) * ... - _Gary W. Adamson_, Aug 30 2016 %F A116525 a(n) = Sum_{k=0..n-1} 10^wt(k), where wt = A000120. - _Mike Warburton_, Mar 14 2019 %F A116525 a(n) = Sum_{k=0..floor(log_2(n))} 10^k*A360189(n-1,k). - _Alois P. Heinz_, Mar 06 2023 %p A116525 a:=proc(n) if n=0 then 0 elif n=1 then 1 elif n mod 2 = 0 then 11*a(n/2) else 10*a((n-1)/2)+a((n+1)/2) fi end: seq(a(n),n=0..42); %t A116525 b[0] := 0; b[1] := 1; b[n_?EvenQ] := b[n] = 11*b[n/2]; b[n_?OddQ] := b[n] = 10*b[(n - 1)/2] + b[(n + 1)/2]; a = Table[b[n], {n, 1, 25}] %Y A116525 Cf. A000120, A006046, A077465, A084230. %Y A116525 Cf. A130665, A116520, A130667, A116522, A161342, A116526, A360189. %K A116525 nonn %O A116525 0,3 %A A116525 _Roger L. Bagula_, Mar 15 2006 %E A116525 Edited by _N. J. A. Sloane_, Apr 16 2005 # Content is available under The OEIS End-User License Agreement: http://oeis.org/LICENSE