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%I A069095 #38 Jan 17 2024 09:07:56
%S A069095 1,1023,59048,1047552,9765624,60406104,282475248,1072693248,
%T A069095 3486725352,9990233352,25937424600,61855850496,137858491848,
%U A069095 288972178704,576640565952,1098437885952,2015993900448,3566920035096,6131066257800
%N A069095 Jordan function J_10(n).
%C A069095 a(n) is divisible by 264 = (2^3)*3*11 = A006863(5), except for n = 1, 2, 3 or 11. See Lugo. - _Peter Bala_, Jan 13 2024
%D A069095 L. Comtet, Advanced Combinatorics, Reidel, 1974, p. 199, #3.
%H A069095 Robert Israel, Table of n, a(n) for n = 1..10000
%H A069095 Michael Lugo, A little number theory problem (2008)
%H A069095 Wikipedia, Jordan's totient function.
%F A069095 a(n) = Sum_{d|n} d^10*mu(n/d).
%F A069095 Multiplicative with a(p^e) = p^(10e)-p^(10(e-1)).
%F A069095 Dirichlet generating function: zeta(s-10)/zeta(s). - _Ralf Stephan_, Jul 04 2013
%F A069095 a(n) = n^10*Product_{distinct primes p dividing n} (1-1/p^10). - _Tom Edgar_, Jan 09 2015
%F A069095 Sum_{k=1..n} a(k) ~ n^11 / (11*zeta(11)). - _Vaclav Kotesovec_, Feb 07 2019
%F A069095 From _Amiram Eldar_, Oct 12 2020: (Start)
%F A069095 lim_{n->oo} (1/n) * Sum_{k=1..n} a(k)/k^10 = 1/zeta(11).
%F A069095 Sum_{n>=1} 1/a(n) = Product_{p prime} (1 + p^10/(p^10-1)^2) = 1.0009955309... (End)
%p A069095 f:= n -> n^10*mul(1-1/p^10, p=numtheory:-factorset(n)):
%p A069095 map(f, [$1..30]); # _Robert Israel_, Jan 09 2015
%t A069095 JordanJ[n_, k_] := DivisorSum[n, #^k*MoebiusMu[n/#] &]; f[n_] := JordanJ[n, 10]; Array[f, 21]
%t A069095 f[p_, e_] := p^(10*e) - p^(10*(e-1)); a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100] (* _Amiram Eldar_, Oct 12 2020 *)
%o A069095 (PARI) for(n=1,100,print1(sumdiv(n,d,d^10*moebius(n/d)),","))
%Y A069095 Cf. A059379 and A059380 (triangle of values of J_k(n)), A000010 (J_1), A007434 (J-2), A059376 (J_3), A059377 (J_4), A059378 (J_5), A069091 - A069094 (J_6 through J_9).
%Y A069095 Cf. A013669.
%K A069095 easy,nonn,mult
%O A069095 1,2
%A A069095 _Benoit Cloitre_, Apr 05 2002
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