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%I A068099 #6 Apr 09 2014 10:13:40
%S A068099 1,1,3,12,108,2712,327240,235617840,1187514095040,47880568312738560,
%T A068099 17374900629326652478080,63050039403700556512496620800
%N A068099 a(1) = 1; a(n+1) = n! sum{k|n} a(k)/k where sum is over positive divisors k of n.
%K A068099 nonn
%O A068099 1,3
%A A068099 _Leroy Quet_, Mar 22 2002

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