# Greetings from The On-Line Encyclopedia of Integer Sequences! http://oeis.org/ Search: id:a067001 Showing 1-1 of 1 %I A067001 #35 Jun 05 2020 06:04:15 %S A067001 1,4,6,24,60,42,160,560,688,308,1120,5040,8760,7080,2310,8064,44352, %T A067001 99456,114576,68712,17556,59136,384384,1055040,1572480,1351840,642824, %U A067001 134596,439296,3294720,10695168,19536000,21778560,14912064,5864640,1038312 %N A067001 Triangle T(n,k) = d(n-k,n), 0 <= k <= n, where d(l,m) = Sum_{k=l..m} 2^k * binomial(2*m-2*k, m-k) * binomial(m+k, m) * binomial(k, l). %C A067001 For an explanation on how this triangular array is related to the Boros-Moll polynomial P_n(x) and the theory in Comtet (1967), see my comments in A223549. For example, the bivariate o.g.f. below follows from the theory in Comtet (1967). - _Petros Hadjicostas_, May 24 2020 %H A067001 Tewodros Amdeberhan and Victor H. Moll, A formula for a quartic integral: a survey of old proofs and some new ones, arXiv:0707.2118 [math.CA], 2007. %H A067001 George Boros and Victor H. Moll, An integral hidden in Gradshteyn and Ryzhik, Journal of Computational and Applied Mathematics, 106(2) (1999), 361-368. %H A067001 William Y. C. Chen and Ernest X. W. Xia, The Ratio Monotonicity of the Boros-Moll Polynomials, arXiv:0806.4333 [math.CO], 2009. %H A067001 William Y. C. Chen and Ernest X. W. Xia, The Ratio Monotonicity of the Boros-Moll Polynomials, Mathematics of Computation, 78(268) (2009), 2269-2282. %H A067001 Louis Comtet, Fonctions génératrices et calcul de certaines intégrales, Publikacije Elektrotechnickog faculteta - Serija Matematika i Fizika, No. 181/196 (1967), 77-87. %H A067001 V. H. Moll, The evaluation of integrals: a personal story, Notices Amer. Math. Soc., 49 (No. 3, March 2002), 311-317. %H A067001 V. H. Moll, Combinatorial sequences arising from a rational integral, Onl. J. Anal. Combin. no 2 (2007) #4. %F A067001 From _Petros Hadjicostas_, May 24 2020: (Start) %F A067001 T(n,k) = 2^(2*n)*A223549(n,n-k)/A223550(n,n-k). %F A067001 Bivariate o.g.f.: Sum_{n,k>=0} T(n,k)*x^n*y^k = sqrt((1 + y)/(1 - 8*x*(1 + y))/(1 + y*sqrt(1 - 8*x*(1 + y)))). (End) %e A067001 Triangle T(n,k) (with rows n >= 0 and columns k = 0..n) starts: %e A067001 1; %e A067001 4, 6; %e A067001 24, 60, 42; %e A067001 160, 560, 688, 308; %e A067001 1120, 5040, 8760, 7080, 2310; %e A067001 ... %p A067001 d := proc(l,m) local k; add(2^k*binomial(2*m-2*k,m-k)*binomial(m+k,m)*binomial(k,l),k=l..m); end: %p A067001 T:= (n, k)-> d(n-k, n): %p A067001 seq(seq(T(n, k), k=0..n), n=0..10); %t A067001 T[n_, k_] := SeriesCoefficient[Sqrt[(1+y)/(1 - 8x (1+y))/(1 + y Sqrt[1 - 8x (1+y)])], {x, 0, n}, {y, 0, k}]; %t A067001 Table[T[n, k], {n, 0, 10}, {k, 0, n}] // Flatten (* _Jean-François Alcover_, Jun 05 2020 *) %o A067001 (PARI) d(l, m) = sum(kk=l, m, 2^kk*binomial(2*m-2*kk,m-kk)*binomial(m+kk,m)*binomial(kk,l)); %o A067001 tabl(nn) = {for (n=0, nn, for (k=0, n, print1(d(n-k, n), ", ");); print(););} \\ _Michel Marcus_, Jul 18 2015 %Y A067001 Column k=0 gives A059304. %Y A067001 Row sums give A002458. %Y A067001 Main diagonal gives A004982. %Y A067001 Cf. A223549, A223550. %K A067001 nonn,tabl %O A067001 0,2 %A A067001 _N. J. A. Sloane_, Feb 16 2002 # Content is available under The OEIS End-User License Agreement: http://oeis.org/LICENSE