Search: a157337 -id:a157337
|
|
|
|
72, 136, 200, 264, 328, 392, 456, 520, 584, 648, 712, 776, 840, 904, 968, 1032, 1096, 1160, 1224, 1288, 1352, 1416, 1480, 1544, 1608, 1672, 1736, 1800, 1864, 1928, 1992, 2056, 2120, 2184, 2248, 2312, 2376, 2440, 2504, 2568, 2632, 2696, 2760, 2824, 2888, 2952
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
The identity (128*n^2+32*n+1)^2-(4*n^2+n)*(64*n+8)^2=1 can be written as A157337(n)^2-A007742(n)*a(n)^2=1. This is the case s=2 of the identity (8*n^2*s^4+8*n*s^2+1)^2-(n^2*s^2+n)*(8*n*s^3+4*s)^2=1. - Vincenzo Librandi, Jan 29 2012
Likewise, the immediate identity (a(n)^2+1)^2-(a(n)^2+2)*a(n)^2 = 1 can be rewritten as A158686(8*n+1)^2-(A158686(8*n+1)+1)*a(n)^2=1. - Bruno Berselli, Feb 13 2012
|
|
LINKS
|
|
|
FORMULA
|
G.f.: 8*(1+7*x)/(x-1)^2. [corrected by Georg Fischer, May 12 2019]
a(n) = 2*a(n-1)-a(n-2). (End)
|
|
MATHEMATICA
|
|
|
PROG
|
(Magma) I:=[72, 136]; [n le 2 select I[n] else 2*Self(n-1)-Self(n-2): n in [1..50]]; // Vincenzo Librandi, Jan 29 2012
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
Search completed in 0.006 seconds
|