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Sums of two powers of 10.
+10
55
2, 11, 20, 101, 110, 200, 1001, 1010, 1100, 2000, 10001, 10010, 10100, 11000, 20000, 100001, 100010, 100100, 101000, 110000, 200000, 1000001, 1000010, 1000100, 1001000, 1010000, 1100000, 2000000, 10000001, 10000010, 10000100, 10001000, 10010000, 10100000, 11000000, 20000000
OFFSET
1,1
COMMENTS
Numbers whose digit sum is 2.
A007953(a(n)) = 2; number of repdigits = #{2,11} = A242627(2) = 2. - Reinhard Zumkeller, Jul 17 2014
By extension, numbers k such that digitsum(k)^2 - 1 is prime. (PROOF: For any number k whose digit sum d > 2, d^2 - 1 = (d+1)*(d-1) and thus is not prime.) - Christian N. K. Anderson, Apr 22 2024
LINKS
Reinhard Zumkeller, Table of n, a(n) for n = 1..10000 (terms 1..48 from Vincenzo Librandi, terms 49..1036 from T. D. Noe)
FORMULA
T(n,k) = 10^(n-1) + 10^(k-1) with 1 <= k <= n.
a(n) = 3*A237424(n) - 1. - Reinhard Zumkeller, Jan 28 2015
EXAMPLE
From Bruno Berselli, Mar 07 2013: (Start)
The triangular array starts (see formula):
2;
11, 20;
101, 110, 200;
1001, 1010, 1100, 2000;
10001, 10010, 10100, 11000, 20000;
100001, 100010, 100100, 101000, 110000, 200000;
1000001, 1000010, 1000100, 1001000, 1010000, 1100000, 2000000;
...
(End)
MATHEMATICA
t = 10^Range[0, 9]; Select[Union[Flatten[Table[i + j, {i, t}, {j, t}]]], # <= t[[-1]] + 1 &] (* T. D. Noe, Oct 09 2011 *)
With[{nn=7}, Sort[Join[Table[FromDigits[PadRight[{2}, n, 0]], {n, nn}], FromDigits/@Flatten[Table[Table[Insert[PadRight[{1}, n, 0], 1, i]], {n, nn}, {i, 2, n+1}], 1]]]] (* Harvey P. Dale, Nov 15 2011 *)
Select[Range[10^9], Total[IntegerDigits[#]] == 2&] (* Vincenzo Librandi, Mar 07 2013 *)
T[n_, k_]:=10^(n-1)+10^(k-1); Table[T[n, k], {n, 8}, {k, n}]//Flatten (* Stefano Spezia, Nov 03 2023 *)
PROG
(Magma) [n: n in [1..10100000] | &+Intseq(n) eq 2]; // Vincenzo Librandi, Mar 07 2013
(Magma) /* As a triangular array: */ [[10^n+10^m: m in [0..n]]: n in [0..8]]; // Bruno Berselli, Mar 07 2013
(Haskell)
a052216 n = a052216_list !! (n-1)
a052216_list = 2 : f [2] 9 where
f xs@(x:_) z = ys ++ f ys (10 * z) where
ys = (x + z) : map (* 10) xs
-- Reinhard Zumkeller, Jan 28 2015, Jul 17 2014
(PARI) a(n)=my(d=(sqrtint(8*n)-1)\2, t=n-d*(d+1)/2-1); 10^d + 10^t \\ Charles R Greathouse IV, Dec 19 2016
(Python)
from itertools import count, islice
def agen(): yield from (10**i + 10**j for i in count(0) for j in range(i+1))
print(list(islice(agen(), 34))) # Michael S. Branicky, May 15 2022
(SageMath)
def A052216(n, k): return 10^(n-1) + 10^(k-1)
flatten([[A052216(n, k) for k in range(1, n+1)] for n in range(1, 13)]) # G. C. Greubel, Feb 22 2024
CROSSREFS
Subsequence of A069263 and A107679. A038444 is a subsequence.
Sums of n powers of 10: A011557 (1), A052217 (3), A052218 (4), A052219 (5), A052220 (6), A052221 (7), A052222 (8), A052223 (9), A052224 (10), A166311 (11), A235151 (12), A143164 (13), A235225(14), A235226 (15), A235227 (16), A166370 (17), A235228 (18), A166459 (19), A235229 (20).
KEYWORD
easy,nonn,tabl
AUTHOR
Henry Bottomley, Feb 01 2000
STATUS
approved
Numbers n with property that sod(n^3) = 6^3.
+10
5
3848163483, 4462569999, 4479677412, 4586158119, 4594661259, 4594665192, 4594700889, 4625720379, 4641588459, 5644008999, 5828410842, 5833034823, 5838252576, 5848025709, 6453471192, 6617331999, 6619097067, 6686657169, 7107126942, 7230291999, 7277907183
OFFSET
1,1
COMMENTS
Numbers n with property that A007953(n^3) = 6^3.
LINKS
EXAMPLE
3848163483^3 = 56984998629886989599887999587, 5+6+9+8+4+9+9+8+6+2+9+8+8+6+9+8+9+5+9+9+8+8+7+9+9+9+5+8+7 = 216 = 6^3.
CROSSREFS
Cf. A054966 Numbers that are congruent to {0, 1, 8} mod 9. A054966 Possible sums of digits of cubes. A067075 a(n) = smallest number m such that the sum of the digits of m^3 is equal to n^3. A007953 Digital sum (i.e., sum of digits) of n.
Numbers n such that sum of digits of n^3 is k^3: A107679 (k=2), A290842 (k=3), A290843 (k=4), A159462 (k=5), this sequence (k=6).
KEYWORD
base,nonn
AUTHOR
Zak Seidov, Apr 12 2009
EXTENSIONS
a(16)-a(21) from Seiichi Manyama, Aug 12 2017
STATUS
approved
Numbers k such that the sum of digits of k^3 is 4^3 = 64.
+10
4
1192, 1366, 1426, 1435, 1753, 1786, 1813, 1816, 1912, 1942, 1999, 2116, 2389, 2395, 2398, 2413, 2566, 2599, 2632, 2635, 2653, 2692, 2713, 2872, 2899, 2992, 3022, 3031, 3103, 3199, 3289, 3295, 3298, 3301, 3355, 3361, 3382, 3394, 3409, 3415, 3442, 3466, 3475
OFFSET
1,1
LINKS
EXAMPLE
1192^3 = 1693669888, 1 + 6 + 9 + 3 + 6 + 6 + 9 + 8 + 8 + 8 = 64 = 4^3.
11*(10^(n+2) + 1) is a term for all n > 0. - Altug Alkan, Aug 12 2017
MATHEMATICA
Select[Range[3500], Total[IntegerDigits[#^3]]==64&] (* Harvey P. Dale, Aug 04 2019 *)
PROG
(PARI) isok(n) = sumdigits(n^3) == 64; \\ Altug Alkan, Aug 12 2017
CROSSREFS
Numbers k such that sum of digits of k^3 is m^3: A107679 (m=2), A290842 (m=3), this sequence (m=4), A159462 (m=5), A159463 (m=6).
Cf. A067075.
KEYWORD
nonn,base
AUTHOR
Seiichi Manyama, Aug 12 2017
STATUS
approved
Numbers k such that the sum of digits of k^3 is 3^3 = 27.
+10
3
27, 33, 36, 39, 42, 54, 57, 69, 72, 75, 78, 84, 87, 93, 105, 108, 111, 114, 135, 138, 147, 162, 165, 168, 174, 177, 219, 222, 225, 228, 231, 234, 258, 267, 270, 273, 276, 285, 291, 294, 312, 318, 321, 330, 342, 345, 348, 351, 360, 369, 381, 384, 390, 405, 417
OFFSET
1,1
COMMENTS
It is obvious that if k is in this sequence, then so is 10*k. Additionally, this sequence contains other infinite subsequences. For example, 10^(2*k) + 10^k + 1 is in this sequence for all k > 0. - Altug Alkan, Aug 12 2017
LINKS
EXAMPLE
27^3 = 19683, 1 + 9 + 6 + 8 + 3 = 27 = 3^3.
PROG
(PARI) isok(n) = sumdigits(n^3) == 27; \\ Altug Alkan, Aug 12 2017
CROSSREFS
Numbers k such that sum of digits of k^3 is m^3: A107679 (m=2), this sequence (m=3), A290843 (m=4), A159462 (m=5), A159463 (m=6).
Cf. A067075.
KEYWORD
nonn,base
AUTHOR
Seiichi Manyama, Aug 12 2017
STATUS
approved

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