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#18 by Vaclav Kotesovec at Tue Oct 11 01:56:08 EDT 2016
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#17 by Vaclav Kotesovec at Tue Oct 11 01:54:28 EDT 2016
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a(n) ~ 2^(n + 3/2) * sqrt(n/Pi). - Vaclav Kotesovec, Oct 11 2016
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| STATUS
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proposed
editing
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#16 by Vladimir Reshetnikov at Mon Oct 10 20:35:08 EDT 2016
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#15 by Vladimir Reshetnikov at Mon Oct 10 20:34:59 EDT 2016
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Recurrence: (n+1)*a(n+1) = 4*a(n) + 4*n*a(n-1).). - _Vladimir Reshetnikov_, Oct 10 2016
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proposed
editing
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#14 by Vladimir Reshetnikov at Mon Oct 10 20:29:42 EDT 2016
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Discussion
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| Mon Oct 10
| 20:32
| Omar E. Pol: The contribution should be signed.
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#13 by Vladimir Reshetnikov at Mon Oct 10 20:29:34 EDT 2016
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Recurrence: (n+1)*a(n+1) = 4*(*a(n) + 4*n*a(n-1)).).
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#12 by Vladimir Reshetnikov at Mon Oct 10 20:28:55 EDT 2016
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Recurrence: (n+1)*a(n+1) = 4*(a(n) + n*a(n-1)).
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approved
editing
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#11 by Peter Luschny at Tue Apr 26 09:39:54 EDT 2016
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#10 by Peter Luschny at Tue Apr 26 09:39:35 EDT 2016
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a(n) = (-2)^n*hypergeom([-n,3/2], [1], 2). - Peter Luschny, Apr 26 2016
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seq(simplify((-2)^n*hypergeom([-n, 3/2], [1], 2)), n=0..29); # Peter Luschny, Apr 26 2016
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approved
editing
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#9 by Harvey P. Dale at Mon Jan 04 10:57:19 EST 2016
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