editing

approved

Harvey P. Dale, <a href="/A152295/b152295.txt">Table of n, a(n) for n = 1..3000</a>

Select[Prime[Range[1000]], AllTrue[{(#-5)/6, 6#+5}, PrimeQ]&] (* This program uses the AllTrue function from Mathematica version 10 *) (* Harvey P. Dale, Jul 29 2014 *)

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editing

_Vladimir Joseph Stephan Orlovsky (4vladimir(AT)gmail.com), _, Dec 02 2008

OEIS Server: https://oeis.org/edit/global/876

Primes of the form : (p-n)/(n+1)=prime and (n+1)*p+n=prime. n=5.

17, 71, 83, 107, 191, 227, 251, 263, 431, 443, 479, 503, 587, 827, 839, 911, 983, 1091, 1151, 1163, 1187, 1619, 1667, 1847, 1907, 2087, 2243, 2459, 2591, 3023, 3467, 4463, 4871, 4943, 5471, 5519, 5651, 5807, 5903, 6131, 6203, 6299, 6311, 6563, 6983, 7127

1,1

This is the general form : (p-n)/(n+1)=primeand(n+1)*p+n=prime; 'Safe' primes and'Sophie Germain' primes just one part of this general form; If n=1 then we got'Safe' primes and'Sophie Germain' primes.

lst={}; n=5; Do[p=Prime[k]; If[PrimeQ[(p-n)/(n+1)]&&PrimeQ[(n+1)*p+n], AppendTo[lst, p]], {k, 7!}]; lst

Cf. A059455, A152292, A152293, A152294

nonn

Vladimir Orlovsky (4vladimir(AT)gmail.com), Dec 02 2008

approved