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Revision History for A085601 (Underlined text is an addition; strikethrough text is a deletion.)

Showing entries 1-10 | older changes
A085601 a(n) = 2 * (4^n + 2^n) + 1.
(history; published version)
#24 by N. J. A. Sloane at Mon Apr 26 20:52:56 EDT 2021
STATUS

proposed

approved

#23 by Kevin Ryde at Mon Apr 26 18:39:21 EDT 2021
STATUS

editing

proposed

#22 by Kevin Ryde at Mon Apr 26 18:39:01 EDT 2021
CROSSREFS

Cf. A343175 (essentially the same).

STATUS

approved

editing

#21 by Joerg Arndt at Sat Dec 12 06:03:36 EST 2020
LINKS

<a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (7,-14,8).)

FORMULA

a(n)^2 = A000051(n)^2 + A028403(n)^2 for A000051(n)>2. - César Aguilera, Nov 29 2020

KEYWORD

nonn,easy,changed

STATUS

editing

approved

#20 by Joerg Arndt at Mon Nov 30 01:13:49 EST 2020
STATUS

proposed

editing

Discussion
Mon Dec 07 01:30
OEIS Server: This sequence has not been edited or commented on for a week
yet is not proposed for review.  If it is ready for review, please
visit https://oeis.org/draft/A085601 and click the button that reads
"These changes are ready for review by an OEIS Editor."

Thanks.
  - The OEIS Server
#19 by Michel Marcus at Sun Nov 29 15:03:58 EST 2020
STATUS

editing

proposed

Discussion
Mon Nov 30 01:13
Joerg Arndt: A000051(1)^2 + A028403(1)^2 = 3^2 + 4^2 = 25 = 5^2, but that is not a(1) but a(0).
#18 by Michel Marcus at Sun Nov 29 15:03:55 EST 2020
LINKS

<a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (7,-14,8)).

STATUS

proposed

editing

#17 by César Aguilera at Sun Nov 29 14:54:17 EST 2020
STATUS

editing

proposed

#16 by César Aguilera at Sun Nov 29 14:53:43 EST 2020
FORMULA

a(n)^2 = A000051(n)^2 + A028403(n)^2 for A000051(n)>2. - César Aguilera, Nov 29 2020

STATUS

approved

editing

#15 by Bruno Berselli at Sat Dec 30 16:14:43 EST 2017
STATUS

reviewed

approved

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Last modified August 31 05:08 EDT 2024. Contains 375550 sequences. (Running on oeis4.)