The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A000911 (Bold, blue-underlined text is an addition; faded, red-underlined text is a ~~deletion~~.)
newer changes | Showing entries 11-20 | older changes

A000911

a(n) = (2n+3)! /( n! * (n+1)! ).
(history; published version)

#40 by Bruno Berselli at Tue Jan 31 09:36:28 EST 2017

STATUS

editing

approved

#39 by Bruno Berselli at Tue Jan 31 09:36:00 EST 2017

FORMULA

From Ilya Gutkovskiy, Jan 31 2017: (Start)

a(n) ~ 2^(2*n+3)*n^(3/2)/sqrt(Pi). - _Ilya Gutkovskiy_, Jan 31 2017(End)

#38 by Bruno Berselli at Tue Jan 31 09:34:44 EST 2017

FORMULA

a(n) ~ 2^(2*n+3)*n^(3/2)/sqrt(Pi). - Ilya Gutkovskiy, Jan 31 2017

STATUS

reviewed

editing

#37 by Anton Mosunov at Tue Jan 31 09:18:48 EST 2017

STATUS

proposed

reviewed

#36 by Anton Mosunov at Tue Jan 31 09:18:38 EST 2017

STATUS

editing

proposed

#35 by Anton Mosunov at Tue Jan 31 09:17:23 EST 2017

FORMULA

Sum_{n>=0} (-1)^n/a(n) = 5*A086466-2 = 2*log(phi)*sqrt(5)-2 = 0.1520447... - Jean-François Alcover, Apr 22 2014 G.f.: 6/(1 - 4*x)^(5/2).

G.f.: 6/(1 - 4*x)^(5/2).

Discussion

Tue Jan 31

09:18

Anton Mosunov: Ilya, I slightly reformatted your update so it looks similar to previous formulas present in the description.

#34 by Anton Mosunov at Tue Jan 31 09:17:04 EST 2017

FORMULA

Sum_{n>=0} (-1)^n/a(n) = 5*A086466-2 = 2*log(phi)*sqrt(5)-2 = 0.1520447... - Jean-François Alcover, Apr 22 2014 G.f.: 6/(1 - 4*x)^(5/2).

From _ a(n) ~ 2^(2*n+3)*n^(3/2)/sqrt(Pi). - _Ilya Gutkovskiy_, Jan 31 2017: (Start)

G.f.: 6/(1 - 4*x)^(5/2).

a(n) ~ 2^(2*n+3)*n^(3/2)/sqrt(Pi). (End)

STATUS

proposed

editing

#33 by Ilya Gutkovskiy at Tue Jan 31 07:16:53 EST 2017

STATUS

editing

proposed

#32 by Ilya Gutkovskiy at Tue Jan 31 06:50:37 EST 2017

FORMULA

From Ilya Gutkovskiy, Jan 31 2017: (Start)

G.f.: 6/(1 - 4*x)^(5/2).

a(n) ~ 2^(2*n+3)*n^(3/2)/sqrt(Pi). (End)

STATUS

approved

editing

#31 by N. J. A. Sloane at Tue Jan 31 01:28:18 EST 2017

STATUS

reviewed

approved