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A133418 revision #4

A133418
Let l(n) = number of letters in n, A005589(n). If l(n) = 4 set a(n) = 0; otherwise a(n) = a(l(n)) + 1.
3
0, 2, 2, 1, 0, 0, 2, 1, 1, 0, 2, 3, 3, 2, 2, 2, 2, 1, 2, 2, 3, 1, 1, 4, 3, 3, 1, 4, 4, 3, 3, 1, 1, 4, 3, 3, 1, 4, 4, 3, 1, 2, 2, 3, 1, 1, 2, 3, 3, 1, 1, 2, 2, 3, 1, 1, 2, 3, 3, 1, 1, 2, 2, 3, 1, 1, 2, 3, 3, 1, 2, 3, 3, 4, 4, 4, 3, 4, 4, 4, 3, 1, 1, 4, 3, 3, 1, 4, 4, 3, 3, 1, 1, 4, 3, 3, 1, 4, 4, 3, 4, 3, 3, 3, 3
OFFSET
0,2
COMMENTS
Based on the observation by Diane Karloff (see A005589) that the trajectory of l always converges to 4.
EXAMPLE
5 has four letters so a(5) = 0. 3 has five letters so a(3) = a(5) + 1 = 1.
CROSSREFS
A variant of A016037.
Sequence in context: A344447 A287385 A191411 * A181169 A029390 A108040
KEYWORD
nonn,word,easy
AUTHOR
N. J. A. Sloane (njas(AT)research.att.com), Nov 27 2007
STATUS
approved