[go: up one dir, main page]

login
A369624
Numbers formed by the rightmost decimal digits of n^(n^n) that are the same as those of n^(n^(n^n)).
6
0, 1, 6, 87, 96, 8203125, 8656, 2343, 56, 289, 0, 6611, 16, 53, 36, 765380859375, 5616, 777, 76, 179, 0, 2421, 6, 47, 4976, 908447265625, 84203776, 83, 96, 669, 0, 6431, 4176, 713, 16, 8046875, 7136, 917, 6, 759, 0, 7641, 6, 1107, 56, 48828125, 9696, 23, 36
OFFSET
0,3
COMMENTS
The common digits might include leading 0's (such as at n = 5) and they are discarded (in particular, a(0) = 0 indicates that the corresponding zero digit term results in a 0 integer entry).
a(k*10) = 0 for every positive integer k, since (k*10)^((k*10)^(k*10)) and (k*10)^((k*10)^((k*10)^(k*10))) have in common only their rightmost (k*10)^(k*10) digits.
LINKS
Jorge Jiménez Urroz and José Luis Andrés Yebra, On the Equation a^x == x (mod b^n), Journal of Integer Sequences, Article 09.8.8, 2009.
Marco Ripà, Congruence speed of tetration bases ending with 0, arXiv:2402.07929 [math.NT], 2024.
Eric Weisstein's World of Mathematics, Joyce Sequence.
FORMULA
a(n) = A002488(n) (mod 10^k), where k is such that n^(n^n) == n^(n^(n^n)) (mod 10^k) and n^(n^n) <> n^(n^(n^n)) (mod 10^(k+1)).
EXAMPLE
For n = 3, 3^(3^3) = 7625597484987 and 3^(3^(3^3)) == 387 (mod 1000) so there are two common final digits a(3) = 87.
CROSSREFS
KEYWORD
sign,base
AUTHOR
Marco Ripà, Jan 27 2024
STATUS
approved