A352161 - OEIS

A352161

Numbers m such that the smallest digit in the decimal expansion of 1/m is k = 8, ignoring leading and trailing 0's.

125, 1125, 1250, 11250, 12500, 112500, 125000, 1125000, 1250000, 11250000, 12500000, 112500000, 125000000, 1125000000, 1250000000

(list; graph; refs; listen; history; text; internal format)

OFFSET

1,1

COMMENTS

Leading 0's are not considered, otherwise every integer >= 11 would be a term.

Trailing 0's are also not considered, otherwise numbers of the form 2^i*5^j with i, j >= 0, apart from 1 (A003592) would be terms.

If t is a term, 10*t is also a term; so, terms with no trailing zeros are all primitive terms: 125, 1125, ...

Note that for k = 7, if any term exists, it must be greater than 10^10. - Jinyuan Wang, Mar 29 2022

LINKS

FORMULA

A352153(a(n)) = 8.

EXAMPLE

m = 125 is a term since 1/125 = 0.008 and the smallest digit after the leading 0's is 8.

m = 1125 is a term since 1/1125 = 0.00088888888... and the smallest digit after the leading 0's is 8.

CROSSREFS

Similar with smallest digit k: A352154 (k=0), A352155 (k=1), A352156 (k=2), A352157 (k=3), A352158 (k=4), A352159 (k=5), A352160 (k=6), A352153 (no known term for k=7), this sequence (k=8), no term (k=9).

KEYWORD

nonn,base,more

AUTHOR

EXTENSIONS

a(9)-a(15) from Jinyuan Wang, Mar 29 2022

STATUS

approved