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Intersection of Beatty sequences for (1+sqrt(5))/2 and sqrt(5).
11

%I #21 Nov 18 2022 07:15:49

%S 4,6,8,11,17,22,24,29,33,35,38,40,42,46,51,53,55,58,64,67,69,71,76,80,

%T 82,84,87,93,98,100,105,111,114,116,118,122,127,129,131,134,140,145,

%U 147,152,156,158,160,163,165,169,174,176,181,187,190,192,194,199

%N Intersection of Beatty sequences for (1+sqrt(5))/2 and sqrt(5).

%C Conjecture: every term of the difference sequence is in {2,3,4,5,6}, and each occurs infinitely many times.

%C From _Clark Kimberling_, Jul 29 2022: (Start)

%C This is the first of four sequences that partition the positive integers. Starting with a general overview, suppose that u = (u(n)) and v = (v(n)) are increasing sequences of positive integers. Let u' and v' be their complements, and assume that the following four sequences are infinite:

%C (1) u ^ v = intersection of u and v (in increasing order);

%C (2) u ^ v';

%C (3) u' ^ v;

%C (4) u' ^ v'.

%C Every positive integer is in exactly one of the four sequences. For A351415, u, v, u', v', are the Beatty sequences given by u(n) = floor(n*(1+sqrt(5))/2) and v(n) = floor(n*sqrt(5)), so that r = (1+sqrt(5))/2, s = sqrt(5), r' = (3+sqrt(5))/2, s' = (5 + sqrt(5))/4.

%C (1) u ^ v = (4, 6, 8, 11, 17, 22, 24, 29, 33, 35, 38, 40, 42, ...) = A351415

%C (2) u ^ v' = (1, 3, 9, 12, 14, 16, 19, 21, 25, 27, 30, 32, ...) = A356101

%C (3) u' ^ v = (2, 13, 15, 20, 26, 31, 44, 49, 60, 62, 73, 78, ...) = A356102

%C (4) u' ^ v' = (5, 7, 10, 18, 23, 28, 34, 36, 39, 41, 47, 52, ...) = A356103

%C (End)

%e The two Beatty sequences are (1,3,4,6,8,9,11,12,14,...) and (2,4,6,8,11,13,15,17,...), with common terms forming the sequence (4,6,8,11,...).

%t z = 200;

%t r = (1 + Sqrt[5])/2; u = Table[Floor[n*r], {n, 1, z}] (* A000201 *)

%t u1 = Take[Complement[Range[1000], u], z] (* A001950 *)

%t r1 = Sqrt[5]; v = Table[Floor[n*r1], {n, 1, z}] (* A022839 *)

%t v1 = Take[Complement[Range[1000], v], z] (* A108598 *)

%t Intersection[u, v] (* A351415 *)

%t Intersection[u, v1] (* A356101 *)

%t Intersection[u1, v] (* A356102 *)

%t Intersection[u1, v1] (* A356103 *)

%Y Cf. A000201, A022839, A296184, A346308, A347469, A347793.

%Y Cf. A001950, A108598, A356101, A356102, A356103, A356104 (results of composition instead of intersections), A190509 (composites, reversed order).

%K nonn

%O 1,1

%A _Clark Kimberling_, Feb 10 2022