[go: up one dir, main page]

login
A328418
Records in A328412.
2
2, 4, 7, 11, 12, 13, 15, 16, 23
OFFSET
1,1
COMMENTS
Companion sequence of A328417.
Conjecture: this sequence is infinite. That is to say, A328412 is unbounded.
EXAMPLE
Let (Z/mZ)* be the multiplicative group of integers modulo m. We have (Z/mZ)* = C_2 X C_60 has 11 solutions, namely m = 143, 155, 175, 183, 225, 244, 286, 310, 350, 366, 450; for all k' < 30, (Z/mZ)* = C_2 X C_(2k') has fewer than 11 solutions. So A328412(30) = 11 is a term.
PROG
(PARI) my(t=0); for(k=1, 5000, if(A328412(k)>t, print1(a(k), ", "); t=A328412(k)))
CROSSREFS
Sequence in context: A333716 A091263 A101430 * A249594 A127575 A240106
KEYWORD
nonn,hard,more
AUTHOR
Jianing Song, Oct 14 2019
STATUS
approved