OFFSET
1,1
COMMENTS
LINKS
EXAMPLE
Let (Z/mZ)* be the multiplicative group of integers modulo m. We have (Z/mZ)* = C_2 X C_60 has 11 solutions, namely m = 143, 155, 175, 183, 225, 244, 286, 310, 350, 366, 450; for all k' < 30, (Z/mZ)* = C_2 X C_(2k') has fewer than 11 solutions. So A328412(30) = 11 is a term.
CROSSREFS
KEYWORD
nonn,hard,more
AUTHOR
Jianing Song, Oct 14 2019
STATUS
approved