A324282 - OEIS

A324282

Lexicographically earliest sequence of different terms starting with a(1) = 10 such that the n-th digit of the sequence, placed after a(n) and then concatenated, produces a term with a parity opposed to the parity of a(n).

10, 1, 2, 3, 4, 5, 6, 7, 8, 9, 12, 14, 11, 16, 13, 18, 20, 22, 15, 24, 26, 28, 17, 19, 21, 23, 25, 30, 32, 27, 29, 31, 33, 35, 37, 34, 36, 38, 40, 39, 42, 41, 44, 43, 46, 48, 45, 50, 47, 49, 52, 51, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 53, 74, 55, 76, 57, 59, 61, 78, 80, 63, 65, 67, 82, 69, 71, 73, 84, 75, 77, 79, 81, 83, 86

(list; graph; refs; listen; history; text; internal format)

OFFSET

1,1

COMMENTS

The sequence is a permutation of the numbers > 0.

LINKS

Jean-Marc Falcoz, Table of n, a(n) for n = 1..10001

EXAMPLE

The 1st digit of the sequence (1) concatenated to the 1st term = 101 (10 -> 101);

the 2nd digit of the sequence (0) concatenated to the 2nd term = 10 (1 -> 10);

the 3rd digit of the sequence (1) concatenated to the 3rd term = 21 (2 -> 21);

the 4th digit of the sequence (2) concatenated to the 4th term = 32 (3 -> 32);

the 5th digit of the sequence (3) concatenated to the 5th term = 43 (4 -> 43);

the 6th digit of the sequence (4) concatenated to the 6th term = 54 (5 -> 54);

the 7th digit of the sequence (5) concatenated to the 7th term = 65 (6 -> 65);

the 8th digit of the sequence (6) concatenated to the 8th term = 76 (7 -> 76);

the 9th digit of the sequence (7) concatenated to the 9th term = 87 (8 -> 87);

the 10th digit of the sequence (8) concatenated to the 10th term = 98 (9 -> 98);

the 11th digit of the sequence (9) concatenated to the 11th term = 129 (12 -> 129);

etc.

CROSSREFS

Cf. A306311, A306321, A324279, A324280 and A324281 where the same idea is used.

Sequence in context: A213790 A240962 A376301 * A085764 A090555 A283393

Adjacent sequences: A324279 A324280 A324281 * A324283 A324284 A324285

KEYWORD

base,nonn

AUTHOR

Eric Angelini and Jean-Marc Falcoz, Feb 20 2019

STATUS

approved