OFFSET
1,3
COMMENTS
In an n-minute race between n competitors numbered 1 to n, where competitor number k runs at speed 1/k rpm for all k, a(n) is the number of overtakings.
FORMULA
a(n) = Sum_{1<=i<j<=n} floor(n*(1/i-1/j)).
a(n) = Sum_{k=0..n-1} T(n,k)*k, where T is A321368 in bivariate form.
MATHEMATICA
a[n_] := Sum[ Sum[ Floor[n*(1/i - 1/j)], {i, 1 , j} ], {j, 1, n} ]; Array[a, 50] (* Amiram Eldar, Nov 08 2018 *)
PROG
(PARI)
a(n)=sum(y=2, n, sum(x=1, y-1, floor(n*(1/x-1/y))))
for(n=1, 80, print1(a(n), ", "))
CROSSREFS
KEYWORD
nonn
AUTHOR
Luc Rousseau, Oct 26 2018
STATUS
approved