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a(n) = (1/3!)*3^(n+1)*(n+5)*(n+1)*(n).
4

%I #27 Jun 25 2017 11:59:39

%S 18,189,1296,7290,36450,168399,734832,3070548,12400290,48715425,

%T 187067232,704690766,2611501074,9542023155,34437376800,122941435176,

%U 434685788658,1523724783237,5299912289520,18305618105250,62824881337218,214364018189079,727538485975056

%N a(n) = (1/3!)*3^(n+1)*(n+5)*(n+1)*(n).

%H <a href="/A288836/b288836.txt">Table of n, a(n) for n = 1..23</a>

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (12, -54, 108, -81).

%F O.g.f.: z*3^2*(2-3*z)/(1-3*z)^4.

%F a(n) = -A287768(n+5,6).

%Y Column k=6 of A287768.

%Y Cf. A288834, A288835, A288838.

%K nonn

%O 1,1

%A _Gregory Gerard Wojnar_, Jun 17 2017