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Positions of 1 in A286807; complement of A286808.
3

%I #4 Jun 07 2017 12:25:30

%S 3,4,6,7,9,11,13,14,16,18,20,22,24,26,28,29,31,33,35,37,39,41,43,45,

%T 47,49,51,53,55,57,59,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,

%U 92,94,96,98,100,102,104,106,108,110,112,114,116,118,120,122

%N Positions of 1 in A286807; complement of A286808.

%C Conjecture: a(n)/n -> 2, and -2 < 2 - a(n)/n < 3 for n >= 1.

%H Clark Kimberling, <a href="/A286809/b286809.txt">Table of n, a(n) for n = 1..10000</a>

%t s = {0, 0}; w[0] = StringJoin[Map[ToString, s]];

%t w[n_] := StringReplace[w[n - 1], {"00" -> "001", "1" -> "101"}]

%t Table[w[n], {n, 0, 8}]

%t st = ToCharacterCode[w[11]] - 48 (* A286807 *)

%t Flatten[Position[st, 0]] (* A286808 *)

%t Flatten[Position[st, 1]] (* A286809 *)

%Y Cf. A286807, A286808.

%K nonn,easy

%O 1,1

%A _Clark Kimberling_, Jun 06 2017