%I #4 Apr 30 2017 11:30:52

%S 3,4,7,8,11,12,15,16,17,18,19,20,23,24,27,28,29,30,31,32,35,36,39,40,

%T 43,44,47,48,51,52,55,56,57,58,59,60,63,64,67,68,69,70,71,72,75,76,79,

%U 80,83,84,87,88,91,92,95,96,97,98,99,100,103,104,107,108

%N Positions of 1 in A285501; complement of A285502.

%C Conjecture: a(n)/n -> (1+sqrt(5))/2 = golden ratio (A001622).

%H Clark Kimberling, <a href="/A285503/b285503.txt">Table of n, a(n) for n = 1..10000</a>

%e As a word, A285501 = 00110011..., in which 1 is in positions 3,4,7,8,11,...

%t s = Nest[Flatten[# /. {0 -> {1, 1}, 1 -> {0, 0, 1, 1}}] &, {0}, 8] (* A285501 *)

%t Flatten[Position[s, 0]] (* A285502 *)

%t Flatten[Position[s, 1]] (* A285503 *)

%Y Cf. A001622, A285501, A285503, A285504.

%K nonn,easy

%O 1,1

%A _Clark Kimberling_, Apr 30 2017