OFFSET
0,2
COMMENTS
The next term has 114 digits.
FORMULA
a(n) = 2^(Fibonacci(2*n)).
MATHEMATICA
Clear[a]; RecurrenceTable[{a[n]==a[n-1]^3/a[n-2], a[0]==1, a[1]==2}, a, {n, 0, 8}]
Clear[a]; a[0]=2; a[n_]:=a[n]=Product[a[j]^(n-j), {j, 0, n-1}]; Flatten[{1, Table[a[n], {n, 1, 8}]}]
Table[2^(Fibonacci[2*n]), {n, 0, 8}]
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Vaclav Kotesovec, May 22 2015
STATUS
approved