%I #12 Jul 03 2014 05:50:17

%S 16,46,109,222,407,690,1099,1669,2437,3445,4737,6363,8376,10834,13797,

%T 17330,21503,26389,32064,38608,46108,54651,64331,75243,87489,101172,

%U 116402,133290,151953,172511,195088,219813,246817,276236,308211,342885,380407,420927,464601,511590

%N Rounded down ratio of area of a unit circle and one of the circles inscribed between a regular n-gon and a circumscribed unit circle.

%H Kival Ngaokrajang, <a href="/A244094/a244094_1.pdf">Illustration of initial terms</a>

%F a(n) = floor(Pi/area(n)) where area(n) = Pi*r(n)^2, r(n) = (1 - cos(Pi/n))/2 = sin(Pi/(2*n))^2, n >= 3.

%o (PARI)

%o {

%o for (n=3, 100,

%o b=Pi*(n-2)/(2*n);

%o r=(1-sin(b))/2;

%o area=Pi*r^2;

%o a=floor(Pi/area);

%o print1(a,", ")

%o )

%o }

%Y Cf. A244093, A244096.

%K nonn,easy

%O 3,1

%A _Kival Ngaokrajang_, Jun 20 2014

%E Edited. Formula simplified - _Wolfdieter Lang_, Jun 27 2014