[go: up one dir, main page]

login
A240905
Smallest k such that the minimal factor in factorization of k! over distinct terms of A050376 is A050376(n), or a(n)=0 if there is no such k.
7
2, 12, 20, 6, 10, 130, 180, 240, 480, 597, 901, 40537, 15841, 23401, 36720, 112321, 20377, 177842
OFFSET
1,1
COMMENTS
a(n) is the smallest k such that the minimal infinitary divisor of k! is A050376(n).
Conjecture. All a(n)>0.
EXAMPLE
Let n=4. A050376(4)=5. For k=2,3,4,5,6, we have the following factorizations over distinct terms of A050376: 2!=2,3!=2*3,4!=2*3*4,5!=2*3*4*5,6!=5*9*16. Only the last factorization begins with 5. So a(4)=6.
KEYWORD
nonn,more
AUTHOR
Vladimir Shevelev, Apr 14 2014
EXTENSIONS
More terms from Peter J. C. Moses, Apr 19 2014
STATUS
approved