OFFSET
1,2
COMMENTS
Row sums give A000203.
LINKS
EXAMPLE
Written as an irregular triangle the sequence begins:
1;
3;
5, -1;
8, -1;
10, -4;
15, -4, 1;
16, -9, 1;
23, -9, 1;
25, -16, 4;
31, -16, 4, -1;
34, -25, 4, -1;
45, -25, 9, -1;
42, -36, 9, -1;
55, -36, 9, -4;
60, -49, 16, -4, 1;
67, -49, 16, -4, 1;
69, -64, 16, -4, 1;
86, -64, 25, -9, 1;
84, -81, 25, -9, 1;
103, -81, 25, -9, 4;
102, -100, 36, -9, 4, -1;
113, -100, 36, -16, 4, -1;
122, -121, 36, -16, 4, -1;
145, -121, 49, -16, 4, -1;
...
For j = 15 the divisors of 15 are 1, 3, 5, 15, therefore the sum of divisors of 15 is 1 + 3 + 5 + 15 = 24. On the other hand the 15th row of triangle is 60, -49, 16, -4, 1, therefore the row sum is 60 - 49 + 16 - 4 + 1 = 24, equalling the sum of divisors of 15.
CROSSREFS
KEYWORD
sign,tabf
AUTHOR
Omar E. Pol, Jan 29 2014
STATUS
approved