[go: up one dir, main page]

login
A236631
Triangle read by rows: T(j,k), j>=1, k>=1, in which column k lists the positive squares repeated k-1 times, except the column 1 which is A123327. The elements of the even-indexed columns are multiplied by -1. The first element of column k is in row k(k+1)/2.
3
1, 3, 5, -1, 8, -1, 10, -4, 15, -4, 1, 16, -9, 1, 23, -9, 1, 25, -16, 4, 31, -16, 4, -1, 34, -25, 4, -1, 45, -25, 9, -1, 42, -36, 9, -1, 55, -36, 9, -4, 60, -49, 16, -4, 1, 67, -49, 16, -4, 1, 69, -64, 16, -4, 1, 86, -64, 25, -9, 1, 84, -81, 25, -9, 1, 103
OFFSET
1,2
COMMENTS
T(j,k) which row j has length A003056(j) hence the first element of column k is in row A000217(j).
Row sums give A000203.
Interpreted as a sequence with index n this is also the first differences of A236630. If a(n) is positive then a(n) is the number of cells turned ON at n-th stage in the structure of A236630. If a(n) is negative then a(n) is the number of cells turned OFF at n-th stage in the structure of A236630.
FORMULA
T(n,1) = A000203(n) + A004125(n).
EXAMPLE
Written as an irregular triangle the sequence begins:
1;
3;
5, -1;
8, -1;
10, -4;
15, -4, 1;
16, -9, 1;
23, -9, 1;
25, -16, 4;
31, -16, 4, -1;
34, -25, 4, -1;
45, -25, 9, -1;
42, -36, 9, -1;
55, -36, 9, -4;
60, -49, 16, -4, 1;
67, -49, 16, -4, 1;
69, -64, 16, -4, 1;
86, -64, 25, -9, 1;
84, -81, 25, -9, 1;
103, -81, 25, -9, 4;
102, -100, 36, -9, 4, -1;
113, -100, 36, -16, 4, -1;
122, -121, 36, -16, 4, -1;
145, -121, 49, -16, 4, -1;
...
For j = 15 the divisors of 15 are 1, 3, 5, 15, therefore the sum of divisors of 15 is 1 + 3 + 5 + 15 = 24. On the other hand the 15th row of triangle is 60, -49, 16, -4, 1, therefore the row sum is 60 - 49 + 16 - 4 + 1 = 24, equalling the sum of divisors of 15.
KEYWORD
sign,tabf
AUTHOR
Omar E. Pol, Jan 29 2014
STATUS
approved