OFFSET
1,2
COMMENTS
Conjecture: a(n) > 0 for all n. Equivalently, any number not divisible by 4 divides infinitely many members of A232637.
LINKS
Charles R Greathouse IV, Table of n, a(n) for n = 1..10000
PROG
(PARI) ok(n)=hammingweight(n)%2 && hammingweight(n\2+1)%2
a(n)=my(k=n+(n-1)\3, m=k); while(!ok(m), m+=k); (m+6)\4 \\ Charles R Greathouse IV, Dec 09 2013
CROSSREFS
KEYWORD
nonn
AUTHOR
Charles R Greathouse IV, Dec 09 2013
STATUS
approved