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Least numbers k for each base b >= 2 such that N = b^(2^n) + k is prime for 6 consecutive values from n = 0 to n = 5
1

%I #5 May 09 2013 13:01:13

%S 15,440,93,1518,1081,8712,52305,32300,5383,8058,7165,196168,405,11456,

%T 81,66432,102745,88848,1071,15206,8607,12228,270185,57668,56895,42322,

%U 339835,120510,3089

%N Least numbers k for each base b >= 2 such that N = b^(2^n) + k is prime for 6 consecutive values from n = 0 to n = 5

%K nonn

%O 2,1

%A _Robin Garcia_, May 08 2013