OFFSET
0,1
COMMENTS
The corresponding left Aurifeuillian factor is A220989.
LINKS
Wikipedia, Cunningham Project
Index entries for linear recurrences with constant coefficients, signature (157,-1884,1728).
FORMULA
Aurifeuillian factorization: 12^(6n+3) + 1 = (12^(2n+1) + 1) * A220989(n) * a(n).
G.f.: -(2736*x^2-1182*x+19) / ((x-1)*(12*x-1)*(144*x-1)). - Colin Barker, Jan 03 2013
MATHEMATICA
Table[12^(2n+1) + 6 * 12^n + 1, {n, 0, 10}]
LinearRecurrence[{157, -1884, 1728}, {19, 1801, 249697}, 20] (* Harvey P. Dale, Mar 26 2022 *)
PROG
(PARI) a(n)=12^(2*n+1)+6*12^n+1 \\ Charles R Greathouse IV, Sep 28 2015
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Stuart Clary, Dec 27 2012
STATUS
approved