OFFSET
1,1
COMMENTS
Row 5 of A208597.
LINKS
R. H. Hardin, Table of n, a(n) for n = 1..210
FORMULA
Empirical: a(n) = (23/12)*n^4 + (23/6)*n^3 + (37/12)*n^2 + (7/6)*n + 1.
Conjectures from Colin Barker, Mar 07 2018: (Start)
G.f.: x*(11 + 22*x + 16*x^2 - 4*x^3 + x^4) / (1 - x)^5.
a(n) = 5*a(n-1) - 10*a(n-2) + 10*a(n-3) - 5*a(n-4) + a(n-5) for n>5.
(End)
EXAMPLE
Some solutions for n=4:
-4 -3 -4 -4 -3 -3 -3 -3 -3 -4 -4 -4 -4 -4 -4 -1
-1 2 3 2 0 2 1 -1 4 2 0 -1 4 0 0 0
4 -2 2 -4 -3 2 2 2 0 0 0 4 -3 2 -1 1
-2 3 0 3 3 -1 -2 0 1 -2 2 1 4 1 2 -1
3 0 -1 3 3 0 2 2 -2 4 2 0 -1 1 3 1
CROSSREFS
KEYWORD
nonn
AUTHOR
R. H. Hardin, Feb 29 2012
STATUS
approved