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A193586
Number of attractors under iteration of sum of squares of digits in base n.
4
1, 5, 1, 6, 9, 13, 10, 8, 9, 9, 20, 13, 12, 35, 7, 15, 7, 21, 27, 37, 24, 36, 32, 26, 10, 36, 27, 28, 10, 56, 22, 26, 23, 63, 39, 27, 19, 67, 9, 36, 40, 54, 54, 48, 18, 73, 52, 75, 18, 117, 52, 74, 22, 65, 48, 53, 45, 44, 43, 18, 30, 67, 39, 49, 87, 111, 15
OFFSET
2,2
COMMENTS
If b>=2 and a>=b^2 then S(a,2,b)<a. For each positive integer a, there is an positive integer m such that S^m(a,2,b)<b^2. (Grundman/Teeple, 2001, Lemma 6 and Corollary 7)
LINKS
H. G. Grundman, E. A. Teeple, Generalized Happy Numbers, Fibonacci Quarterly 39 (2001), nr. 5, p. 462-466.
EXAMPLE
In the decimal system all integers go to (1) or (4, 16, 37, 58, 89, 145, 42, 20) under the iteration of sum of squares of digits, hence there is one fixed point and one 8-cycle. Therefore a(10) = 1 + 8 = 9.
MAPLE
S:=proc(n, p, b) local Q, k, N, z; Q:=[convert(n, base, b)]; for k from 1 do N:=Q[k]; z:=convert(sum(N['i']^p, 'i'=1..nops(N)), base, b); if not member(z, Q) then Q:=[op(Q), z]; else Q:=[op(Q), z]; break; fi; od; return Q; end:
NumberOfAttractors:=proc(b) local A, i, Q; A:=[]: for i from 1 to b^2 do Q:=S(i, 2, b); A:=[op(A), Q[nops(Q)]]; od: return(nops({op(A)})); end:
seq(NumberOfAttractors(b), b=2..50);
CROSSREFS
Sequence in context: A164105 A262153 A160824 * A007397 A362489 A204203
KEYWORD
nonn,base
AUTHOR
Martin Renner, Jul 31 2011
STATUS
approved