A184632 - OEIS

A184632

Floor(1/{(8+n^4)^(1/4)}), where {}=fractional part.

1, 4, 13, 32, 62, 108, 171, 256, 364, 500, 665, 864, 1098, 1372, 1687, 2048, 2456, 2916, 3429, 4000, 4630, 5324, 6083, 6912, 7812, 8788, 9841, 10976, 12194, 13500, 14895, 16384, 17968, 19652, 21437, 23328, 25326, 27436, 29659, 32000, 34460, 37044, 39753, 42592, 45562, 48668, 51911, 55296, 58824, 62500, 66325, 70304, 74438, 78732, 83187, 87808, 92596, 97556, 102689, 108000

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OFFSET

1,2

LINKS

Table of n, a(n) for n=1..60.

Index entries for linear recurrences with constant coefficients, signature (3, -2, -2, 3, -1).

FORMULA

a(n)=floor(1/{(8+n^4)^(1/4)}), where {}=fractional part.

It appears that a(n)=3a(n-1)-2a(n-2)-2a(n-3)+3a(n-4)-a(n-5) for n>=7.

MATHEMATICA

p[n_]:=FractionalPart[(n^4+8)^(1/4)];

q[n_]:=Floor[1/p[n]];