OFFSET
1,1
COMMENTS
From Robert Israel, Jun 01 2018: (Start)
Since q^2-4 = (q-2)(q+2), for this to be a semiprime requires q-2 and q+2 to be primes.
All terms == 3 (mod 6), thus q/3 is an odd prime. (End)
LINKS
Robert Israel, Table of n, a(n) for n = 1..2365
EXAMPLE
9^2-4 = 77 = 7*11 and 9^2+4 = 85 = 5*13 are semiprimes created by q=9, which adds the semiprime q=9 to the sequence.
MAPLE
N:= 10^5: # to get all terms <= N
P:= select(isprime, [seq(i, i=3..N/3, 2)]):
select(q -> isprime(q-2) and isprime(q+2) and numtheory:-bigomega(q^2+4)=2, 3*P); # Robert Israel, Jun 01 2018
MATHEMATICA
f[n_]:=Last/@FactorInteger[n]=={1, 1}||Last/@FactorInteger[n]=={2}; lst={}; Do[If[f[n], a=n^2-4; b=n^2+4; If[f[a]&&f[b], AppendTo[lst, n]]], {n, 9!}]; lst
PROG
(Magma) IsSemiprime:=func<n | &+[d[2]: d in Factorization(n)] eq 2>; [n: n in [4..7*10^4] | IsSemiprime(n) and IsSemiprime(n^2+4) and IsSemiprime(n^2-4)]; // Vincenzo Librandi, Jun 02 2018
CROSSREFS
KEYWORD
nonn
AUTHOR
Vladimir Joseph Stephan Orlovsky, Feb 09 2010
EXTENSIONS
Definition reworded by R. J. Mathar, Mar 14 2010
STATUS
approved