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a(n) = n^10*(n^2 + 1)/2.
8

%I #10 Sep 08 2022 08:45:49

%S 0,1,2560,295245,8912896,126953125,1118624256,7061881225,34896609280,

%T 142958160441,505000000000,1582182900661,4489008906240,11717971807165,

%U 28491583515136,65161494140625,141287244169216,292319115565105

%N a(n) = n^10*(n^2 + 1)/2.

%H Vincenzo Librandi, <a href="/A170794/b170794.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_13">Index entries for linear recurrences with constant coefficients</a>, signature (13,-78,286,-715,1287,-1716,1716, -1287,715,-286,78,-13,1).

%F G.f.: (x + 2547*x^2 + 262043*x^3 + 5274105*x^4 + 33383142*x^5 + 80828562*x^6 + 80828562*x^7 + 33383142*x^8 + 5274105*x^9 + 262043*x^10 + 2547*x^11 + x^12)/(1-x)^13. - _G. C. Greubel_, Dec 06 2017

%t Table[n^10*(n^2+1)/2, {n,0,30}] (* _G. C. Greubel_, Dec 06 2017 *)

%o (Magma)[n^10*(n^2+1)/2: n in [0..20]]; // _Vincenzo Librandi_, Aug 26 2011

%o (PARI) for(n=0,30, print1(n^10*(n^2+1)/2, ", ")) \\ _G. C. Greubel_, Dec 30 2017

%K nonn,easy

%O 0,3

%A _N. J. A. Sloane_, Dec 11 2009