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a(n) = n^6*(n^2 + 1)/2.
1

%I #16 Sep 08 2022 08:45:49

%S 0,1,160,3645,34816,203125,863136,2941225,8519680,21789081,50500000,

%T 108065221,216483840,410278765,741659296,1287140625,2155872256,

%U 3499947505,5526986400,8515304461,12832000000,18954312741,27494626720,39229510585,55133208576

%N a(n) = n^6*(n^2 + 1)/2.

%H G. C. Greubel, <a href="/A168527/b168527.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_09">Index entries for linear recurrences with constant coefficients</a>, signature (9, -36, 84, -126, 126, -84, 36, -9, 1).

%F G.f.: (x + 151*x^2 + 2241*x^3 + 7687*x^4 + 7687*x^5 + 2241*x^6 + 151*x^7 + x^8)/(1 - x)^9. - _G. C. Greubel_, Jul 25 2016

%t Table[n^6*(n^2 + 1)/2, {n,0,25}] (* _G. C. Greubel_, Jul 25 2016 *)

%t LinearRecurrence[{9,-36,84,-126,126,-84,36,-9,1},{0,1,160,3645,34816,203125,863136,2941225,8519680},30] (* _Harvey P. Dale_, May 10 2018 *)

%o (Magma) [n^6*(n^2 + 1)/2: n in [0..30]]; // _Vincenzo Librandi_, Jul 25 2016

%K nonn

%O 0,3

%A _N. J. A. Sloane_, Dec 11 2009