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A158485 a(n) = 14*n^2 - 1. 5
13, 55, 125, 223, 349, 503, 685, 895, 1133, 1399, 1693, 2015, 2365, 2743, 3149, 3583, 4045, 4535, 5053, 5599, 6173, 6775, 7405, 8063, 8749, 9463, 10205, 10975, 11773, 12599, 13453, 14335, 15245, 16183, 17149, 18143, 19165, 20215, 21293, 22399 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
The identity (14*n^2-1)^2-(49*n^2-7)*(2*n)^2=1 can be written as a(n)^2-A158484(n)*A005843(n)^2=1.
Sequence found by reading the line from 13, in the direction 13, 55,..., in the square spiral whose vertices are the generalized enneagonal numbers A118277. Also sequence found by reading the same line in the square spiral whose edges have length A195019 and whose vertices are the numbers A195020. - Omar E. Pol, Sep 13 2011
LINKS
FORMULA
a(n) = 3*a(n-1) -3*a(n-2) +a(n-3).
G.f: x*(-13-16*x+x^2)/(x-1)^3.
From Amiram Eldar, Feb 04 2021: (Start)
Sum_{n>=1} 1/a(n) = (1 - (Pi/sqrt(14))*cot(Pi/sqrt(14)))/2.
Sum_{n>=1} (-1)^(n+1)/a(n) = ((Pi/sqrt(14))*csc(Pi/sqrt(14)) - 1)/2.
Product_{n>=1} (1 + 1/a(n)) = (Pi/sqrt(14))*csc(Pi/sqrt(14)).
Product_{n>=1} (1 - 1/a(n)) = csc(Pi/sqrt(14))*sin(Pi/sqrt(7))/sqrt(2). (End)
MATHEMATICA
LinearRecurrence[{3, -3, 1}, {13, 55, 125}, 50]
PROG
(Magma) I:=[13, 55, 125]; [n le 3 select I[n] else 3*Self(n-1)-3*Self(n-2)+1*Self(n-3): n in [1..40]];
(PARI) a(n) = 14*n^2-1
CROSSREFS
Sequence in context: A027000 A198160 A029531 * A274973 A005902 A051798
KEYWORD
nonn,easy
AUTHOR
Vincenzo Librandi, Mar 20 2009
STATUS
approved

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Last modified August 30 00:57 EDT 2024. Contains 375520 sequences. (Running on oeis4.)