[go: up one dir, main page]

login
Bisection of A054353.
3

%I #11 Jun 26 2022 23:51:01

%S 1,5,7,10,14,17,20,23,25,29,32,34,37,41,43,46,49,52,55,59,61,64,68,71,

%T 73,76,79,82,86,88,91,95,98,101,104,106,109,113,116,118,122,125,128,

%U 131,134,137,141,143,146,149,152,155,158,161,164,168,170,173,176,179,182

%N Bisection of A054353.

%F a(n) = A054353(2n-1).

%F A000002(a(n))=1 and A000002(a(n)+1)=2.

%F n such that A078649(A054353(a(n)-1)-a(n)+2)-A054353(a(n)-1)=2. [From _Benoit Cloitre_, Feb 08 2009]

%Y Partial sums of A332273.

%K nonn

%O 1,2

%A _Benoit Cloitre_, Feb 07 2009