OFFSET
0,1
COMMENTS
Culler & Shalen show a bound of log(3)/2 on maximal injectivity under certain circumstances, see links.
Equals arctanh(1/2), the rapidity of an object traveling at half the speed of light. - Sean Stroud, May 13 2019
LINKS
Marc Culler and Peter B. Shalen, Betti numbers and injectivity radii, Proceedings of the American Mathematical Society, Vol. 137, No. 11 (2009), pp. 3919-3922; preprint, arXiv:0902.0014 [math.GT], 2009.
R. S. Melham and A. G. Shannon, Inverse Trigonometric Hyperbolic Summation Formulas Involving Generalized Fibonacci Numbers, The Fibonacci Quarterly, Vol. 33, No. 1 (1995), pp. 32-40.
Michael Penn, This gnarly integral is actually easy??, YouTube video, 2023.
FORMULA
Equals arctanh(1/2) = arccoth(2) = Integral_{x>2} 1/(x^2-1) dx. - Jean-François Alcover, Jun 04 2013
From Amiram Eldar, Aug 05 2020: (Start)
Equals Sum_{k>=0} 1/((2*k+1) * 2^(2*k+1)).
Equals Integral_{x=0..oo} 1/(exp(x) + 2) dx. (End)
Equals Sum_{k>=1} arctanh(1/Fibonacci(2*k+2)) (Melham and Shannon, 1995). - Amiram Eldar, Jan 15 2022
log(3)/2 = Sum_{n >= 1} 1/(n*P(n, 2)*P(n-1, 2)), where P(n, x) denotes the n-th Legendre polynomial. The first 10 terms of the series gives the approximation log(3)/2 = 0.54930614433(10...), correct to 11 decimal places. - Peter Bala, Mar 16 2024
EXAMPLE
0.54930614433405484569762261846...
MATHEMATICA
RealDigits[Log[3]/2, 10, 120][[1]] (* Harvey P. Dale, Apr 13 2016 *)
PROG
(PARI) log(3)/2 \\ Charles R Greathouse IV, May 15 2019
CROSSREFS
KEYWORD
AUTHOR
Jonathan Vos Post, Feb 03 2009
EXTENSIONS
All digits were wrong. Corrected by N. J. A. Sloane, Feb 05 2009
Offset 0 from Michel Marcus, May 13 2019
STATUS
approved