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A154820
Numbers whose trajectory under iteration of sum of cubes of digits eventually turns out to follow the cyclic iteration of 133, 55, 250.
4
4, 13, 25, 28, 31, 40, 46, 52, 55, 64, 82, 103, 130, 133, 205, 208, 250, 256, 265, 280, 289, 298, 301, 310, 313, 331, 349, 394, 400, 406, 439, 448, 460, 484, 493, 502, 505, 520, 526, 550, 562, 589, 598, 604, 625, 640, 652, 679, 697, 769, 796, 802, 820, 829
OFFSET
1,1
COMMENTS
All the numbers are of the form 3n+1.
Subsequence of A165336. - Reinhard Zumkeller, Sep 17 2009
EXAMPLE
Taking 40 for example,
4^3 + 0^3 = 64;
6^3 + 4^3 = 280;
2^3 + 8^3 + 0^3 = 520;
5^3 + 2^3 + 0^3 = 133;
1^3 + 3^3 + 3^3 = 55;
5^3 + 5^3 = 250.
MAPLE
A055012 := proc(n) local a, d ; a := 0 ; for d in convert(n, base, 10) do a := a+d^3; od; a ; end: isA154820 := proc(n) local traj, t ; t := n ; traj := {} ; while true do if t in traj then if t in {133, 55, 250} then RETURN(true) ; else RETURN(false) ; fi; else traj := traj union {t} ; t := A055012(t) ; fi; od: end: for n from 1 to 1000 do if isA154820(n) then printf("%d, ", n) ; fi; od: # R. J. Mathar, Jan 18 2009
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Avik Roy (avik_3.1416(AT)yahoo.co.in), Jan 15 2009
EXTENSIONS
Extended by R. J. Mathar, Jan 18 2009
Edited by Charles R Greathouse IV, Aug 02 2010
STATUS
approved