OFFSET
1,2
COMMENTS
Double sum ratio is: A055998
FORMULA
a(n) =1/2)*(n + 2)*(n + 3)*(n + 4)*Sum[Sum[Sum[Sum[k^2 - 1, {k, 1, m}], {m, 1, j}], {j, 1, l}], {l, 1, n}]/Sum[Sum[Sum[Sum[k, {k, 1, m}], {m, 1, j}], { j, 1, l}], {l, 1, n}]=(1/6)*(-1 + n)(2 + n)(3 + n)(7 + n)
G.f.: x^2*(-30+50*x-31*x^2+7*x^3)/(-1+x)^5. - R. J. Mathar, Nov 14 2007
MATHEMATICA
h[n_] = (1/2)*(n + 2)*(n + 3)*(n + 4)*Sum[Sum[Sum[Sum[k^2 - 1, {k, 1, m}], {m, 1, j}], {j, 1, l}], {l, 1, n}]/Sum[Sum[Sum[Sum[k, {k, 1, m}], {m, 1, j}], {j, 1, l}], {l, 1, n}]; Table[h[n], {n, 1, 30}]
CROSSREFS
KEYWORD
nonn
AUTHOR
Roger L. Bagula, Jul 22 2007
STATUS
approved