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a(1)=1. a(n+1) = a(n) + a(floor(sqrt(n))).
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%I #8 Jan 22 2019 22:56:12

%S 1,2,3,4,6,8,10,12,14,17,20,23,26,29,32,35,39,43,47,51,55,59,63,67,71,

%T 77,83,89,95,101,107,113,119,125,131,137,145,153,161,169,177,185,193,

%U 201,209,217,225,233,241,251,261,271,281,291,301,311,321,331,341,351

%N a(1)=1. a(n+1) = a(n) + a(floor(sqrt(n))).

%e a(26) = a(25) + a(floor(sqrt(25))) = 71 + a(5) = 71 + 6 = 77.

%p a[1]:=1: for n from 1 to 75 do a[n+1]:=a[n]+a[floor(sqrt(n))] od: seq(a[n],n=1..75); # _Emeric Deutsch_, Feb 24 2007

%K nonn

%O 1,2

%A _Leroy Quet_, Feb 20 2007

%E More terms from _Emeric Deutsch_, Feb 24 2007