OFFSET
0,3
COMMENTS
Term-by-term square of sequence with e.g.f.: exp(x+m/2*x^2) is given by e.g.f.: exp(x/(1-m*x))/sqrt(1-m^2*x^2) for all m.
FORMULA
Equals term-by-term square of A115331 which has e.g.f.: exp(x+5/2*x^2).
D-finite with recurrence: a(n) = (5*n-4)*a(n-1) + 5*(n-1)*(5*n-4)*a(n-2) - 125*(n-1)*(n-2)^2*a(n-3). - Vaclav Kotesovec, Jun 26 2013
a(n) ~ 1/2*exp(2*sqrt(n/5)-n-1/10)*5^n*n^n. - Vaclav Kotesovec, Jun 26 2013
MATHEMATICA
CoefficientList[Series[E^(x/(1-5*x))/Sqrt[1-25*x^2], {x, 0, 20}], x]* Range[0, 20]! (* Vaclav Kotesovec, Jun 26 2013 *)
PROG
(PARI) a(n)=local(m=5); n!*polcoeff(exp(x/(1-m*x+x*O(x^n)))/sqrt(1-m^2*x^2+x*O(x^n)), n)
CROSSREFS
KEYWORD
nonn
AUTHOR
Paul D. Hanna, Jan 20 2006
STATUS
approved