%I #13 Jan 22 2016 06:43:23

%S 1379454720,14182439040,680489641226538823680000,

%T 15229814702070563916152832000,34111227434420791224041472000,

%U 1423615645454579571642097845619575340668304766095889698652160000000

%N Multiperfect numbers, sigma(n) = k*n, which are divisible by their sums of prime factors with and without repetition.

%C Conjecture: the sequence is finite.

%H Achim Flammenkamp, <a href="http://wwwhomes.uni-bielefeld.de/achim/mpn.html">The Multiply Perfect Numbers Page</a> (See here for the latest information about the search)

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/MultiperfectNumber.html">Multiperfect numbers</a>

%e a(1)= 1379454720 = 2^8*3*5*7*19*37*73;

%e sopfr(1379454720), with repetition = 160 = 2^5*5;

%e sopfr(1379454720), without repetition = 146 = 2*73.

%Y Cf. A091443, A114887.

%K fini,nonn

%O 1,1

%A _Sven Simon_, Feb 19 2006