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A079359
Iterate the process: "sum of terms of n-th run" on the Kolakoski sequence until all runs have length 1.
0
1, 8, 1, 4, 1, 4, 6, 4, 1, 6, 1, 4, 8, 1, 4, 1, 8, 1, 4, 1, 8, 4, 1, 8, 1, 4, 8, 1, 4, 1, 8, 1, 8, 1, 4, 1, 4, 6, 4, 1, 6, 1, 4, 1, 4, 8, 1, 4, 6, 4, 1, 8, 4, 1, 8, 1, 4, 1, 8, 1, 4, 1
OFFSET
1,2
COMMENTS
Is it enough to apply the process three times only to obtain all runs of length 1? Then all terms should have values among 1,4,6 or 8.
EXAMPLE
Kolakoski sequence begins 1,2,2,1,1,2,1,2,2,1,2,2,1,1,2,1,1,2,2, When process is applied once: 1,2+2,1+1,2,1,2+2,1,2+2, --> 1,4,2,2,1,4,1,4,...Twice: 1,4,2+2,1,4...->1,4,4,1,4 ... Three times -> 1,8,1,4...
CROSSREFS
Cf. A000002.
Sequence in context: A176457 A110194 A199283 * A010156 A197590 A370067
KEYWORD
nonn
AUTHOR
Benoit Cloitre, Feb 15 2003
STATUS
approved