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a(n) = 2^(2^n-n-2).
2

%I #24 Aug 28 2020 03:25:52

%S 1,8,1024,33554432,72057594037927936,

%T 664613997892457936451903530140172288,

%U 113078212145816597093331040047546785012958969400039613319782796882727665664

%N a(n) = 2^(2^n-n-2).

%C Integer values of 1/(2-Sum_{i=1..m} i/2^i).

%C The next term a(9) has 151 digits, and is too large to include in data. - _Bernard Schott_, Aug 27 2020

%p Data := [seq(2^(2^n-n-2), n = 2..8)]; \\ _Bernard Schott_, Aug 26 2020

%t Table[2^(2^n - n - 2), {n, 2, 8}] (* _Amiram Eldar_, Aug 27 2020 *)

%Y Cf. A036799.

%Y Subsequence of A289585.

%Y Cf. A000225, A020491, A058891.

%K nonn

%O 2,2

%A _Benoit Cloitre_, Oct 25 2002