%I #12 Nov 28 2013 15:22:21

%S 15,21,27,30,51,56,57,63,69,75,84,87,89,90,99,100,102,108,111,113,123,

%T 124,129,130,132,135,138,139,153,156,159,165,166,171,183,192,195,197,

%U 201,207,210,215,216,220,221,232,246,251,258,263,264,267,273,279,283

%N Numbers n such that (50n-6) divides C(3n,n)*2^n.

%C Previous name was "Numbers n such that C(3n,n)*2^n/(50n-6) is an integer".

%o (PARI) isok(n) = ((binomial(3*n, n)*2^n) % (50*n-6)) == 0; \\ _Michel Marcus_, Nov 28 2013

%K easy,nonn

%O 1,1

%A _Benoit Cloitre_, Aug 13 2002

%E New name suggested by _Ralf Stephan_ and entered by _Michel Marcus_, Nov 28 2013