%I #6 Apr 09 2014 10:13:40

%S 1,1,3,12,108,2712,327240,235617840,1187514095040,47880568312738560,

%T 17374900629326652478080,63050039403700556512496620800

%N a(1) = 1; a(n+1) = n! sum{k|n} a(k)/k where sum is over positive divisors k of n.

%K nonn

%O 1,3

%A _Leroy Quet_, Mar 22 2002