%I #19 Sep 28 2023 15:54:12

%S 1,1,5,39,437,6051,99425,1893917,41077012,1000000001,27011044252,

%T 801840699303,25952747043667,909698753958571,34333545124721025,

%U 1388255822130839284,59875111056395524697,2743914679527468673294,133153224151130627642479,6821144143666773728762208

%N Number of digits in n^(n^(n-1)).

%F a(n) = floor(n^(n-1)*log(n)/log(10)) + 1. - _Benoit Cloitre_, Feb 20 2002

%e a(4) = 39 as 4^(4^3) = 4^64 = 3.4028236692... * 10^38.

%Y Cf. A054382, A055642, A089210.

%K nonn,base

%O 1,3

%A _Amarnath Murthy_, Jan 05 2002

%E More terms from _Benoit Cloitre_, Feb 20 2002

%E Offset corrected by _Georg Fischer_, Sep 28 2023