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A058860
Number of 2-connected rooted cubic planar maps with n faces.
7
1, 3, 19, 128, 909, 6737, 51683, 407802, 3293497, 27122967, 227095683, 1928656876, 16582719509, 144125955717, 1264625068163, 11190598332502, 99776445196977, 895685185070155, 8090065969366259, 73480719648381240, 670821169614526749
OFFSET
4,2
LINKS
Z. Gao and N. C. Wormald, Enumeration of rooted cubic planar maps
Z. Gao and N. C. Wormald, Enumeration of rooted cubic planar maps, Annals of Combinatorics, 6 (2002), no. 3-4, 313-325.
FORMULA
G.f.: x^2*(f-x)*(1-2*x)/(1+x), where f is defined by 16*x^2*f^3 + (8*x^4+24*x^3+72*x^2+8*x)*f^2 + (x^6+6*x^5-5*x^4-40*x^3+3*x^2-14*x+1)*f - x^4-3*x^3+13*x^2-x=0. - Emeric Deutsch, Nov 30 2005
From Gheorghe Coserea, Jul 14 2018: (Start)
G.f. y=A(x) satisfies:
0 = 16*y^3 - 8*x*(2*x - 1)*(x^2 + 8*x + 1)*y^2 + x^2*(2*x - 1)^2*(x^4 + 20*x^3 + 50*x^2 - 16*x + 1)*y - x^6*(2*x - 1)^3*(x^2 + 11*x - 1).
0 = x^3*(2*x - 1)^3*(x - 2)*(4*x - 5)*(2*x^2 + 10*x - 1)*y''' - x^2*(2*x - 1)^2*(96*x^5 + 188*x^4 - 1570*x^3 + 1791*x^2 - 481*x + 35)*y'' + 12*x*(2*x - 1)*(48*x^6 + 104*x^5 - 898*x^4 + 1186*x^3 - 514*x^2 + 95*x - 5)*y' - 6*(256*x^7 + 608*x^6 - 5456*x^5 + 8292*x^4 - 4962*x^3 + 1525*x^2 - 220*x + 10)*y.
(End)
EXAMPLE
G.f. = x^4 + 3*x^5 + 19*x^6 + 128*x^7 + 909*x^8 + 6737*x^9 + 51683*x^10 + ... - Michael Somos, Jul 22 2018
MAPLE
eq:=16*x^2*f^3+(8*x^4+24*x^3+72*x^2+8*x)*f^2+(x^6+6*x^5-5*x^4-40*x^3+3*x^2-14*x+1)*f-x^4-3*x^3+13*x^2-x: f:=sum(A[j]*x^j, j=1..35): for n from 1 to 35 do A[n]:=solve(coeff(expand(eq), x^n)=0) od: C2:=x^2*(f-x)*(1-2*x)/(1+x): C2ser:=series(C2, x=0, 30): seq(coeff(C2ser, x^n), n=4..26); # Emeric Deutsch, Nov 30 2005
PROG
(PARI)
F = x^2*(z - x)*(1 - 2*x)/(1 + x);
G = 16*x^4*z^3 + x*(8*x^4 + 24*x^3 + 72*x^2 + 8*x)*z^2 + (x^6 + 6*x^5 -5*x^4 -40*x^3 + 3*x^2 - 14*x + 1)*z - x^3 - 3*x^2 + 13*x - 1;
Z(N) = {
my(z0 = 1 + O('x^N), z1=0, n=1);
while (n++,
z1 = z0 - subst(G, 'z, z0)/subst(deriv(G, 'z), 'z, z0);
if (z1 == z0, break()); z0 = z1); z0;
};
seq(N) = Vec(subst(F, 'z, 'x*Z(N+1)));
seq(21)
\\ test: y=Ser(seq(303), 'x)*x^4; 0 == 16*y^3 - 8*x*(2*x - 1)*(x^2 + 8*x + 1)*y^2 + x^2*(2*x - 1)^2*(x^4 + 20*x^3 + 50*x^2 - 16*x + 1)*y - x^6*(2*x - 1)^3*(x^2 + 11*x - 1)
\\ Gheorghe Coserea, Jul 14 2018
CROSSREFS
KEYWORD
nonn
AUTHOR
N. J. A. Sloane, Jan 06 2001; revised Feb 17 2006
EXTENSIONS
More terms from Emeric Deutsch, Nov 30 2005
STATUS
approved