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floor[2^n/Fibonacci(n)].
1

%I #2 Mar 30 2012 18:51:28

%S 2,4,4,5,6,8,9,12,15,18,23,28,35,43,53,66,82,101,125,155,191,236,292,

%T 361,447,552,683,844,1044,1290,1595,1971,2437,3012,3723,4602,5689,

%U 7032,8692,10744,13280,16415,20291,25081,31002,38320,47366,58548,72370

%N floor[2^n/Fibonacci(n)].

%C Growth of a(n) is roughly 4/(1+sqrt(5)) or about 1.236...

%F a(n) = [A000079(n)/A000045(n)] = (A000079(n) - A057862(n))/A000045(n)

%K nonn

%O 1,1

%A _Henry Bottomley_, Sep 08 2000