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A034973
Number of distinct prime factors in central binomial coefficients C(n, floor(n/2)), the terms of A001405.
11
0, 1, 1, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 8, 8, 8, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 9, 9, 10, 10, 10, 10, 10, 10, 10, 10, 12, 12, 13, 13, 12, 12, 12, 12, 12, 13, 14, 14, 14, 14, 14, 14, 14, 14, 14, 14, 15, 15, 14, 14, 15, 15, 15, 15, 16
OFFSET
1,4
COMMENTS
Sequence is not monotonic. E.g., a(44)=10, a(45)=9 and a(46)=10. The number of prime factors of n! is pi(n), but these numbers are lower.
Prime factors are counted without multiplicity. - Harvey P. Dale, May 20 2012
EXAMPLE
a(25) = omega(binomial(25,12)) = omega(5200300) = 6 because the prime factors are 2, 5, 7, 17, 19, 23.
MATHEMATICA
Table[PrimeNu[Binomial[n, Floor[n/2]]], {n, 90}] (* Harvey P. Dale, May 20 2012 *)
PROG
(PARI) a(n)=omega(binomial(n, n\2)) \\ Charles R Greathouse IV, Apr 29 2015
CROSSREFS
KEYWORD
nonn,easy,nice
AUTHOR
STATUS
approved