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A020666
a(n)^n is the least n-th power containing every digit.
5
1023456789, 32043, 2326, 763, 309, 159, 56, 104, 49, 36, 25, 15, 25, 17, 17, 15, 16, 7, 5, 6, 6, 5, 11, 9, 14, 5, 5, 5, 5, 9, 5, 8, 11, 4, 4, 6, 5, 7, 3, 5, 4, 4, 6, 4, 3, 6, 3, 3, 4, 4, 5, 4, 3, 6, 4, 4, 3, 4, 4, 3, 3, 3, 3, 3, 3, 4, 3, 2, 3, 2, 3, 3, 3, 3, 4, 3, 3, 3, 2, 3, 4, 2, 3, 2, 3, 3, 2, 2, 2
OFFSET
1,1
COMMENTS
It is extremely probable that a(n) = 2 for all n >= 169.
PROG
(Python)
def a(n):
if n == 1: return 1023456789
an = 2
while not(len(set(str(an**n))) == 10): an += 1
return an
print([a(n) for n in range(1, 90)]) # Michael S. Branicky, Jul 04 2021
CROSSREFS
KEYWORD
nonn,base
STATUS
approved